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[1487][BOM] 자식 BOM 조회 쿼리 컬럼 의미 수정 (PACKAGE_ITEM_ID=자식, ITEM_ID=부모) #485

Merged
ysCha merged 1 commits from dev into dev-deploy 2026-05-04 17:27:21 +09:00
Conversation 0 Commits 1 Files Changed 2 +6 -6
2 changed files with 6 additions and 6 deletions
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6
src/main/resources/mappers/displayItem/displayItemMapper.xml
View File

@ -138,7 +138,7 @@
<select id="selectItemBomList" parameterType="String" resultType="com.interplug.qcast.biz.displayItem.dto.ItemResponse" > <select id="selectItemBomList" parameterType="String" resultType="com.interplug.qcast.biz.displayItem.dto.ItemResponse" >
/* sqlid : com.interplug.qcast.displayItem.selectItemBomList */ /* sqlid : com.interplug.qcast.displayItem.selectItemBomList */
SELECT SELECT
PI.ITEM_ID PI.PACKAGE_ITEM_ID AS ITEM_ID
, PI.AMOUNT AS BOM_AMOUNT , PI.AMOUNT AS BOM_AMOUNT
, MI.ITEM_NO , MI.ITEM_NO
, MI.ITEM_NAME , MI.ITEM_NAME
@ -157,10 +157,10 @@
, '0' AS OPEN_FLG , '0' AS OPEN_FLG
FROM M_PACKAGE_ITEM PI WITH (NOLOCK) FROM M_PACKAGE_ITEM PI WITH (NOLOCK)
INNER JOIN M_ITEM MI WITH (NOLOCK) INNER JOIN M_ITEM MI WITH (NOLOCK)
ON PI.ITEM_ID = MI.ITEM_ID ON PI.PACKAGE_ITEM_ID = MI.ITEM_ID
LEFT OUTER JOIN M_ITEM_INFO MII LEFT OUTER JOIN M_ITEM_INFO MII
ON MI.ITEM_ID = MII.ITEM_ID ON MI.ITEM_ID = MII.ITEM_ID
WHERE PI.PACKAGE_ITEM_ID = #{itemId} WHERE PI.ITEM_ID = #{itemId}
AND MI.DEL_FLG = 0 AND MI.DEL_FLG = 0
</select> </select>

6
src/main/resources/mappers/estimate/estimateMapper.xml
View File

@ -376,7 +376,7 @@
<select id="selectItemMasterBomList" parameterType="String" resultType="com.interplug.qcast.biz.estimate.dto.ItemResponse"> <select id="selectItemMasterBomList" parameterType="String" resultType="com.interplug.qcast.biz.estimate.dto.ItemResponse">
/* sqlid : com.interplug.qcast.displayItem.selectItemBomList */ /* sqlid : com.interplug.qcast.displayItem.selectItemBomList */
SELECT SELECT
PI.ITEM_ID PI.PACKAGE_ITEM_ID AS ITEM_ID
, PI.AMOUNT AS BOM_AMOUNT , PI.AMOUNT AS BOM_AMOUNT
, I.ITEM_NO , I.ITEM_NO
, I.ITEM_NAME , I.ITEM_NAME
@ -391,10 +391,10 @@
, '0' AS SALE_PRICE , '0' AS SALE_PRICE
FROM M_PACKAGE_ITEM PI WITH (NOLOCK) FROM M_PACKAGE_ITEM PI WITH (NOLOCK)
INNER JOIN M_ITEM I WITH (NOLOCK) INNER JOIN M_ITEM I WITH (NOLOCK)
ON PI.ITEM_ID = I.ITEM_ID ON PI.PACKAGE_ITEM_ID = I.ITEM_ID
INNER JOIN M_ITEM_INFO II WITH (NOLOCK) INNER JOIN M_ITEM_INFO II WITH (NOLOCK)
ON I.ITEM_ID = II.ITEM_ID ON I.ITEM_ID = II.ITEM_ID
WHERE PI.PACKAGE_ITEM_ID = #{itemId} WHERE PI.ITEM_ID = #{itemId}
AND I.DEL_FLG = 0 AND I.DEL_FLG = 0
</select> </select>