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점 8개 오류

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hyojun.choi 2024-07-22 17:03:32 +09:00
parent e34f3c002a
commit ae5009ba2b
1 changed files with 12 additions and 12 deletions
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24
src/util/canvas-util.js
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@ -38,7 +38,7 @@ export function actionHandler(eventData, transform, x, y) {
// define a function that can keep the polygon in the same position when we change its width/height/top/left
export function anchorWrapper(anchorIndex, fn) {
return function(eventData, transform, x, y) {
return function (eventData, transform, x, y) {
let fabricObject = transform.target
let originX = fabricObject?.points[anchorIndex].x - fabricObject.pathOffset.x
let originY = fabricObject.points[anchorIndex].y - fabricObject.pathOffset.y
@ -365,11 +365,11 @@ export const sortedPoints = (points) => {
for (let i = 0; i < copyPoints.length; i++) {
// y값이 같은 point가 많은 경우 그 중 x값이 가장 큰걸 찾는다.
const temp = copyPoints.filter((point) => point.y === currentPoint.y)
// temp중 x값이 가장 큰 값
const max = temp.reduce((prev, current) => (prev.x >= current.x ? prev : current))
resultPoints.push(max)
currentPoint = max
copyPoints.splice(copyPoints.indexOf(max), 1)
// temp중 x값이 가장 큰 값 copyPoint보다 큰값
const min = temp.reduce((prev, current) => (prev.x <= current.x ? prev : current))
resultPoints.push(min)
currentPoint = min
copyPoints.splice(copyPoints.indexOf(min), 1)
index++
break
}
@ -378,12 +378,12 @@ export const sortedPoints = (points) => {
for (let i = 0; i < copyPoints.length; i++) {
// x값이 같은 point가 많은 경우 그 중 y값이 가장 큰걸 찾는다.
const temp = copyPoints.filter((point) => point.x === currentPoint.x)
// temp중 y값이 가장 큰 값
const max = temp.reduce((prev, current) => (prev.y >= current.y ? prev : current))
// temp중 y값이 가장 작은 값
const min = temp.reduce((prev, current) => (prev.y <= current.y ? prev : current))
resultPoints.push(max)
currentPoint = max
copyPoints.splice(copyPoints.indexOf(max), 1)
resultPoints.push(min)
currentPoint = min
copyPoints.splice(copyPoints.indexOf(min), 1)
index++
break
}
@ -447,4 +447,4 @@ export function calculateDistance(point, line) {
const numerator = Math.abs((y2 - y1) * x0 - (x2 - x1) * y0 + x2 * y1 - y2 * x1)
const denominator = Math.sqrt(Math.pow(y2 - y1, 2) + Math.pow(x2 - x1, 2))
return numerator / denominator
}
}